MA15-08 Maths Coming soon
Equations of Perpendicular Lines
MA15-08
This lesson is coming soon.
In this lesson
Use the negative-reciprocal gradient rule to find the equation of a line perpendicular to a given line, then find where that new line crosses the axes correctly.
What it covers
- The negative-reciprocal rule: flip the fraction, then change its sign
- Finding the equation of a line perpendicular to a given line, through a stated point
- Finding where a line crosses the axes: set y = 0 for the x-axis, set x = 0 for the y-axis
Key words
For: AQA GCSE 8300, Edexcel GCSE 1MA1, Eduqas GCSE C300, OCR GCSE J560, Edexcel IGCSE 4MA1, Cambridge IGCSE 0580
On the specification
| Board | Spec | Statement |
|---|---|---|
| AQA GCSE 8300 | A9 | Plot graphs of equations that correspond to straight-line graphs in the coordinate plane |
| Edexcel GCSE 1MA1 | A9 | Plot graphs of equations that correspond to straight-line graphs in the coordinate plane; use the form y = mx + c to identify parallel lines; find the equation of the line through two given points or through one point with a given gradient |
| Eduqas GCSE C300 | HA9 | Plot graphs of equations that correspond to straight-line graphs in the coordinate plane; use the form y = mx + c to identify parallel and perpendicular lines; find the equation of the line through two given points, or through one point with a given gradient |
| OCR GCSE J560 | 7.02b | Identify and find equations of parallel lines. |
| Edexcel IGCSE 4MA1 | H3.3G | Find the equation of a straight line parallel to a given line; find the equation of a straight line perpendicular to a given line |
| Cambridge IGCSE 0580 | C3.7 | Extended content only. |
| Cambridge IGCSE 0580 | E3.7 | Find the gradient and equation of a straight line perpendicular to a given line. |
For teachers
This GCSE Maths lesson teaches equations of perpendicular lines. By the end, students should be able to use the negative-reciprocal gradient rule to find the equation of a line perpendicular to a given line, then find where that new line crosses the axes correctly. It works through two worked examples and the mistakes examiners report.